1.

Choose the correct answer. ∫19x−4x2dx equals to (a)19sin−1(9x−88)+C(b)12sin−1(8x−99)+C(c)13sin−1(9x−88)+C(d)12sin−1(9x−89)+C

Answer»

Choose the correct answer.
∫19x−4x2dx equals to
(a)19sin−1(9x−88)+C(b)12sin−1(8x−99)+C(c)13sin−1(9x−88)+C(d)12sin−1(9x−89)+C



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