1.

Choose the correct answer in the given question. ∫√1+x2dx is equal to (a)x2√1+x2+12log∣∣x+√1+x2∣∣+C(b)23(1+x2)32+C(c)23x(1+x2)32+C(d)x22√1+x2+12x2log|x+√1+x2|

Answer»

Choose the correct answer in the given question.
1+x2dx is equal to
(a)x21+x2+12logx+1+x2+C(b)23(1+x2)32+C(c)23x(1+x2)32+C(d)x221+x2+12x2log|x+1+x2|



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