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Choose the correct answerThe value of the integral `int1/3 1((x-x^3)^(1/3))/(x^4)dx`is(A) 6 (B)0 (C) 3 (D) 4 |
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Answer» Correct Answer - a `"Let I "=int_(1//3)^(1)((x-x^(3))^(1/3))/(x^(4))dx` `=int_(1//3)^(1)((x^(3))^(1//3)((x)/(x^(3))-(x^(3))/(x^(3)))^(1//3))/(x^(4))dx` `=int_(1//3)^(1)(((1)/(x^(2))-1))/(x^(3))dx` `" Let " (1)/(x^(2))=t rArr (-2)/(x^(3)) dx=dt rArr (dx)/(x^(3)) =(dt)/((-2))` `x=1 rArr t=1 ` ` "and " x=(1)/(3) rArr t=3^(2)=9` `:. I= int_(9)^(1) (t-1)^(1//3) (dt)/((-2)) =(1)/(2) [((t-1)^(1/3+1))/((1)/(3)+1)]_(9)^(1)` `= -(1)/(2) xx(3)/(4) [(t-1)^(4/3)]_(9)^(1) =-(3)/(8)[(1-1)^(4/3)-(9-1)^(4/3)]` `=-(3)/(8)[0-(2^(3))^(4/3)]=-(3)/(8)xx(-16)=6` |
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