Choose the correct match.

1.	Choose the correct match.
Answer» `18mlH_(2)O` at `4^(@)C` contains `6.023xx10^(24)` electrons 11200 ml of `CO_(2)` at STP contains `6.023xx10^(23)` OXYGEN atoms. 5600ml of `CH_(4)` at 273 K and 2 atm contains `12.04xx10^(23)` hydrogen atom. 5600 ml of `CH_(4)` at STP contains `1.505xx10^(23)` METHANE molecules. Solution :a) 18 ml implies 18 gm = 1 mole = 10 moles of `e^(-)` b) 11200 ml = 0.5 moles of `CO_(2)` = 1 moles of O atoms c) 5600 ml at 2 atm implies 11200 at 1 atm = 0.5 moles of `CH_(4)=4xx0.5` = 2 moles of H atoms d) 5600 ml at STP implies 0.25 moles of `CH_(4)` molecules

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