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Choose the correct or the most suitable answer from the given four alternatives.The equation of the circle passing through (1,5) and (4, 1) and touching y-axis is x2 + y2 – 5x – 6y + 9 + λ(4x + 3y – 19) = 0 where λ is equal to … (a) 0, -40/9(b) 0 (c) 40/9(d) -40/9 |
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Answer» (a) 0, -40/9 x2 + y2 – 5x – 6y + 9 + λ(4x + 3y -19) = 0 ie., x2 + y2 + x(4λ – 5) + y(3λ – 6) + 9 — 19λ = 0 Since it touches y axis x = 0 ⇒ y2 + y(3λ – 6) + 9 – 19λ = 0 It is a quadratic in y, Since the circle touches y axis the roots must be equal ⇒ b2 – 4ac = 0 ie.,(3λ – 6)2 – 4(1) (9 – 19λ) = 0 Solving we get λ = o or -40/9 |
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