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Choose the correct rate law for the elementary reversible reaction 3A ⇌ B + 2C.(a) –rA = kCA^3 – CBCC^2/KC(b) –rA = k[CA^3 – CBCC^2KC](c) –rA = k[CA^3 – CBCC^2]/KC(d) –rA = k[CA^3 – CBCC^2/KC]The question was posed to me in an online interview.I would like to ask this question from Reversible Reactions Rate Laws topic in portion Rate Laws and Stoichiometry of Chemical Reaction Engineering |
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Answer» Correct choice is (d) –rA = K[CA^3 – CBCC^2/KC] |
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