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Chord joining A(theta_1)" and "B(theta_2) is reflected by the ellipse,(x^2)/(a^2)+(y^2)/(b^2)=1, at B, if AB is a focal chord and the reflected ray meets the ellipse again at C(theta_3) , then (Given theta_1,theta_2 ne (nx)/(2),n in Z) (where e equal to eccentricity of ellipse) |
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Answer» `E=|(COS((theta_1-theta_2)/(2)))/(cos((theta_1+theta_2)/(2)))|` |
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