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Chords equidistant from the center of a circle are equal in length. |
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Answer» OX=OY `In/_OAX and /_ODY` OA=OD(radii) OX=OY(given) `/_OXA-/_OYD(90^0)` `/_OAX and /_ODY` AX=DY AB=CD=PQ so, chords are equal. |
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