1.

Chords equidistant from the center of a circle are equal in length.

Answer» OX=OY
`In/_OAX and /_ODY`
OA=OD(radii)
OX=OY(given)
`/_OXA-/_OYD(90^0)`
`/_OAX and /_ODY`
AX=DY
AB=CD=PQ
so, chords are equal.


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