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Circumradius of a `Delta ABC` is 2, O is the circumcentre, H is the orthocentre then- `1/64(AH^2+BC^2)(BH^2+AC^2)(CH^2+AB^2)` is equal toA. 64B. 16C. `1/64`D. 1 |
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Answer» Correct Answer - 1 `AH^(2)+BC^(2)=4R^(2)cos^(2)A+4Rsin^(2)A=4R^(2)` `rArr1/64(AH^(2)+BC^(2))(BH^(2)+AC^(2))(CH^(2)+AB^(2))` `(64R^(6))/64=R^(6)=64` |
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