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(cl ciliary muscles. (d) iris.A person needs a lens of power -5.5 dioptres for correcting his distant vision. Forcorrecting his near vision he needs a lens of power +1.5 dioptre. What is the focallength of the lens required for correcting fil distant vision, and (i) near vision?cm in front of the eve. What is the nature and

Answer»

(1). Given that, D =-5.5then focal length =1/D100/-5.5 (1m=100cm)-18.18cm is the focal length of lens with -5.5 power(2)Given that, D=1.5then focal length =1/D

Given that D =-5.5then focal length =1/D100/-5.5 (1m =100cm) -18.18cm is the focal length of eye lens with -5.5 DDistant vision=f=-DDistant vision= 18.18cm(2)given D =1.5then focal length =1/D 100/1.5=66.6cmNear vision

(i)For distant visionPower of lens=-5.5 Dtherefore focal length=1/-5.5 m=(1x10)/55 m=0.18m(ii) for near visionpower=+1.5 Dtherefore focal length=1/1.5m=(1x10)/15m=0.66m



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