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(cl ciliary muscles. (d) iris.A person needs a lens of power -5.5 dioptres for correcting his distant vision. Forcorrecting his near vision he needs a lens of power +1.5 dioptre. What is the focallength of the lens required for correcting fil distant vision, and (i) near vision?cm in front of the eve. What is the nature and |
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Answer» (1). Given that, D =-5.5then focal length =1/D100/-5.5 (1m=100cm)-18.18cm is the focal length of lens with -5.5 power(2)Given that, D=1.5then focal length =1/D Given that D =-5.5then focal length =1/D100/-5.5 (1m =100cm) -18.18cm is the focal length of eye lens with -5.5 DDistant vision=f=-DDistant vision= 18.18cm(2)given D =1.5then focal length =1/D 100/1.5=66.6cmNear vision (i)For distant visionPower of lens=-5.5 Dtherefore focal length=1/-5.5 m=(1x10)/55 m=0.18m(ii) for near visionpower=+1.5 Dtherefore focal length=1/1.5m=(1x10)/15m=0.66m |
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