Class 10 Maths MCQ Questions of Surface areas and volumes with Answers is recommended for the students. Students attempt to solve these questions first and afterward check with the appropriate answer. This practice will assist to gain problem-solving abilities and build their confidence level.

Students are encouraged to solve the MCQ Questions of Surface areas and volumes to know various ideas. Practicing the MCQ question for Class 1O Maths of Surface areas and volumes with answers will support your confidence subsequently assisting you with scoring great in the exam. Solve the underneath given Class 10 Maths MCQ Questions of Surface areas and volumes with Answers and check your answers with the detailed answers here.

Practice Class 10 MCQ Questions for Maths

1.  During conversion of a solid from one shape to another, the volume of the new shape will

(a) increase
(b) decrease
(c) remain unaltered
(d) be doubled

2.  A right circular cylinder of radius r cm and height h cm (h>2r) just encloses a sphere of diameter

(a) r cm
(b) 2r cm
(c) h cm
(d) 2h cm

3. If two solid hemispheres of same base radii r, are joined together along their bases, then curved surface area of this new solid is

(a) 4πr²
(b) 6πr²
(c) 3πr²
(d) 8πr²

4. The shape of an ice-cream cone is a combination of:

(a) Sphere + cylinder
(b) Sphere + cone
(c) Hemisphere + cylinder
(d) Hemisphere + cone

5.  If a cone is cut parallel to the base of it by a plane in two parts, then the shape of the top of the cone will be a:

(a) Sphere
(b) Cube
(c) Cone itself
(d) Cylinder

6. A cylindrical pencil sharpened at one edge is combination of:

(a) a cone and a cylinder
(b) frustum of a cone and cylinder
(c) a hemisphere and a cylinder
(d) four cylinders

7.  A shuttle cock used for playing badminton has the shape of a combination of:

(а) a cylinder and a sphere
(b) a cylinder and a hemisphere
(c) a cone and a sphere
(d) a frustum of a cone and a hemisphere

8.  The radius of a wire is decreased to one third. If volume remains the same, the length will become:

(a) 3 times
(b) 6 times
(c) 9 times
(d) 27 times

9. A cylinder and a cone area of same base radius and of same height. The ratio of the volume of cylinder to that of cone is:

(a) 3 : 1
(b) 1 : 3
(c) 2 : 3
(d) 1 : 1

10. If the surface areas of two spheres are in ratio 16 : 9, then their volumes will be in the ratio:

(a) 27 : 64
(b) 64 : 27
(c) 4 : 3
(d) 3 : 4

11. A solid cylinder of radius r and height h is placed over other cylinder of same height and radius. The total surface area of the shape so formed is

(a) 4πrh + 4πr²
(b) 4πrh − 4πr²
(c) 4πrh + 2πr²           
(d) 4πrh − 2πr²

12. The radii of the top and bottom of a bucket of slant height 45cm are 28cm and 7 cm respectively. The curved surface area of the bucket is:

(a) 4950 cm²
(b) 4951 cm²
(c) 4952 cm²
(d) 4953 cm²

13. If we cut a cone in two parts by a plane parallel to the base, then the bottom part left over is the:

(a) Cone
(b) Frustum of cone
(c) Sphere
(d) Cylinder

14. If r is the radius of the sphere, then the surface area of the sphere is given by;

(a) 4 π r²
(b) 2 π r²
(c) π r²
(d) 4/3 π r²

15. If we change the shape of an object from a sphere to a cylinder, then the volume of cylinder will

(a) Increase
(b) Decrease
(c) Remains unchanged
(d) Doubles

16. The radius of the top and bottom of a bucket of slant height 35 cm are 25 cm and 8 cm. The curved surface of the bucket is:

(a) 4000 sq.cm
(b) 3500 sq.cm
(c) 3630 sq.cm
(d) 3750 sq.cm

17. The total surface area of a hemispherical solid having radius 7 cm is

(a) 462 cm²
(b) 294 cm²
(c) 588 cm²
(d) 154 cm²

18. A solid formed on revolving a right angled triangle about its height is

(a) cylinder
(b) sphere
(c) right circular cone
(d) two cones

19. If we join two hemispheres of same radius along their bases, then we get a;

(a) Cone
(b) Cylinder
(c) Sphere
(d) Cuboid

20. Two identical solid hemispheres of equal base radius r cm are stuck together along their bases. The total surface area of the combination is 

(a) 6πr²
(b) 5πr²
(c) 4πr²
(d) 3πr²

Answer:

1. Answer:  (c) remain unaltered

Explanation: During conversion of one solid shape to another, the volume of the new shape will remain unaltered.

2. Answer: (b) 2r cm

Explanation: Because the sphere is enclosed inside the cylinder, therefore the diameter of sphere is equal to the diameter of cylinder which is 2r cm.

3. Answer: (a) 4πr²

Explanation: Because curved surface area of a hemisphere is and here we join two solid hemispheres along their bases of radii r, from which we get a solid sphere.

Hence the curved surface area of new solid = 2πr² + 2πr² = 4πr²  

4. Answer: (d) Hemisphere + cone

Explanation: The shape of an ice-cream cone is a combination of a hemisphere and a cone.

5. Answer: (c) Cone itself

Explanation: If we cut a cone into two parts parallel to the base, then the shape of the upper part remains the same.

6. Answer: (a) a cone and a cylinder

7. Answer: (d) a frustum of a cone and a hemisphere

8. Answer: (c) 9 times

9. Answer: (a) 3 : 1

10. Answer: (b) 64 : 27

11. Answer: (c) 4πrh + 2πr²           

Explanation: Since the total surface area of cylinder of radius r and height h = 2πrh + 2πr².

When one cylinder is placed over the other cylinder of same height and radius,

Then height of new cylinder = 2h

And radius of the new cylinder = r

Therefore total surface area of new cylinder

= 2πr (2h) + 2πr²

= 4πrh + 2πr²  

12. Answer: (a) 4950 cm²

Explanation: Curved Surface area of the bucket = π (R + r) l

⇒ Curved surface area of the bucket = π (28 + 7) X 45

⇒ Curved surface area of the bucket = 4950 cm²  

13. Answer: (b) Frustum of cone

14. Answer: (a) 4 π r²

Explanation: If r is the radius of the sphere, then the surface area of the sphere is given by 4 π r².

15. Answer: (c) Remains unchanged

Explanation: If we change the shape of a three-dimensional object, the volume of the new shape will be same.

16. Answer: (c) 3630 sq.cm

Explanation: Curved surface of bucket = π(R₁ + R₂) x slant height (l)

Curved Surface = (22/7) x (25 + 8) x 35

CSA = 22 x 33 x 5 = 3630 sq.cm.

17. Answer: (a) 462 cm²
Explanation: Reason: Total surface area of hemisphere = 3πr² 

= 3 × 22/7 × 7 × 7 = 462 cm²  

18. Answer: (c) right circular cone

19. Answer: (c) Sphere

Explanation: If we join two hemispheres of same radius along their bases, then we get a Sphere.

20. Answer: (c) 4πr²

Explanation: When two hemispheres are joined together along their bases, a sphere of the same base radius is formed.

Curved Surface Area of a sphere = 4πr²

Click here for practice more MCQ questions from Chapter Surface Areas and Volumes Class 10 Maths