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Class 8 Maths MCQ Questions of Comparing Quantities with Answers? |
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Answer» These Class 8 Maths MCQ Questions of Comparing Quantities with Answers are prepared by the subject experts from Sarthaks are according to the CBSE syllabus and NCERT guidelines. The chapter deals with the concept of ratios and percentages, along with other main topics and concepts. Students can also refer to Maths formulas for Class 8 Comparing Quantities Roots for better exam preparation and score more marks. The objective types questions (MCQ questions for class 8 Maths) are also available chapter-wise at Sarthaks eConnect to make students learn each concept thoroughly and help them to score better marks in exams. These MCQ Questions for Class 8 Comparing Quantities will allow students a chance to test their knowledge and also prepare for the examination. Practice MCQ Question for Class 8 Maths chapter-wise 1. The ratio of 50 paise to Rs. 1 is (a) 1 : 2 2. The ratio of 10 m to 1 km is (a) 1 : 10 3. The ratio of Speed of a cycle 15 km per hour to the speed of scooter 30 km per hour is 1:2 (a) True 4. The ratio 1 : 4 converted to percentage is (a) 50% 5. The fraction 2/5 converted to percentage is (a) 20% 6. Out of 40 students in a class, 25% passed. How many students passed? (a) 20 7. Out of 100 students of a class, 30% like to watch T.V. How many students like to watch T.V. ? (a) 70 8. There are 50 students in a class of which 40 are boys and the rest are girls. The ratio of the number of boys and number of girls is (a) 2:3 9. 40% of 50 students of a class are good at Science. How many students are not good at Science ? (a) 20 10. Apala has Rs 200 with her. She spent 80% amount she had. How much money is left with her ? (a)Rs 10 11. The marked price of a book is Rs 100. The shopkeeper gives 25% discount on it. What is the sale price of the book? (a) Rs 100 12. A shopkeeper offers 10% discount on the marked price of his articles and still makes a profit of 20%. What is the actual cost of the article marked Rs.500 for him? (a) Rs 350 13. Meenu purchased a fridge for Rs 10000 and sold it for Rs 8000. Find her loss. (a) Rs 8000 14. Saroj purchased a fan for Rs 1000 and sold it for Rs 1200. What is her profit ? (a) Rs 1000 15. Vimla purchased a watch for Rs 500. She sold it at a loss of 20%. Find the selling price. (a) Rs 500 16. Kanti purchased a sewing machine for Rs 2000. She sold it at a loss of 40%. Find the selling price. (a) Rs 1200 17. If 60% of x is 1200 , then the value of ‘x’ is (a) 1000 18. The list price of an article is Rs.220. If it is sold at a discount of 20% , what is its selling price (a) 100 19. A table marked at Rs.15000 is available for Rs.14400 . Find the discount percent? (a) 2% 20. The present population of a town is 25,000. It grows at 4%, 5% and 8% during first year, second year and third year respectively, the population after 3 years is (a) 29,484 21. The C.I. on a certain sum for 2 years is Rs 410 and S.I. is Rs 400. What is the rate of interest per annum? (a) 5% 22. What sum lent out at Cl will amount to Rs. 968 in 2 years at 10% p.a. interest? (a) Rs. 800 23. The ratio of speed of cycle 12 km per hour to the speed of scooter 36 km per hour is (a) 1:2 24. Waheeda bought an air cooler for Rs. 3300 including a tax of 10%. The price of the air cooler before VAT was added is: (a) Rs. 2000 25. A sum of money, at compound interest, yields Rs. 200 and Rs. 220 at the end of first and second year respectively. The rate % is: (a) 20 Answer: 1. Answer: (a) 1 : 2 Explanation: Rs 1 = 100 paise 50 paise : 100 paise or 50 : 100 or 1 : 2. 2. Answer: (c) 1 : 100 Explanation: 1 km = 1000 m 10 m : 1000 m or 10 : 1000 or 1 : 100 3. Answer: (a) True Explanation: Required Ratio is = 15/30 = 1/2 = 1 : 2 4. Answer: (b) 25% Explanation: 1 : 4 = 1/4 x 100% = 25%. 5. Answer: (c) 40% Explanation: 2/5 = 2/5 x 100% = 40% 6. Answer: (b) 10 Explanation: Out of 100, passed = 25 ∴ Out of 40, passed = 25/100 x 40 = 10. or 25% of 40 = 25/100 x 40 = 10 7. Answer: (d) 30% Explanation: Number of students who like to watch T.V. = 30% of 100 = 30/100 x 100 = 30 8. Answer: (c) 4:1 Explanation: Number of Girls = 50 – 40 = 10 Required ratio = 40 : 10 = 4 : 1 9. Answer: (b) 30 Explanation: Out of 100, good at Science = 40 ∴ Out of 50, good at Science = 40/100 × 50 = 20. or Number of students good at science = 40% of 50 = 40/100 x 50 = 20 ∴ Number of students not good at Science = 50 – 20 = 30 10. Answer: (d) Rs 40 Explanation: Out of Rs 100, money spent = Rs 80 ∴ Out of Rs 200, money spent = 80/100 x 200 = Rs 160 or Money spent = 80% of Rs 200 = 200 x 80/100 = Rs 60 ∴ Money left = Rs 200 – Rs 160 = Rs 40 11. Answer: (d) Rs 75 Explanation: Discount on Rs 100 = 25 ∴ Sale price = 100 – 25 = Rs 75 12. Answer: (b) Rs 375 Explanation: M.P = Rs. 500 Discount = 10% ∴ S.P. = Rs.500 - 10% of Rs.500 = 90% of Rs.500 = 90/100 × Rs.500 = Rs.450 Profit = 20% C.P. \(=\frac{450\times 100}{120}\) = Rs.375 13. Answer: (c) Rs 2000 Explanation: Loss = C.P. – S.P. = 10000 – 8000 = Rs 2000 14. Answer: (c) Rs 200 Explanation: Gain = S.P. – C.P. = 1200 – 1000 = Rs 200 15. Answer: (b) Rs 400 Explanation: 100 – 20 = 80 ∵ If C.P. is 100, then S.P. = Rs 80 ∴ If C.P. is Rs 500, then S.P. = 80/100 x 500 = Rs 400 16. Answer: (a) Rs 1200 Explanation: 100 – 40 = 60 ∵ If C.P. is Rs 100, then S.P. = Rs 60 ∴ If C.P. is Rs 2000, then S.P. = 60/100 x 2000 = Rs 1200 17. Answer: (b) 2000 Explanation: Given that 60% of x is 1200 \(\frac{60}{100}\times x=1200\) \(x=1200\times\frac{100}{60}\). x = 2000 18. Answer: (c) 176 Explanation: List (Marked) Price of the frock = 220, Rate of discount = 20% Amount of discount \(=\frac{20}{100}\times220\) = 44 ∴ Selling Price of the frock = Marked Price − Discount = 220−44 = 176 19. Answer: (b) 4% Explanation: Discount = \(\%\frac{15,000-14,400}{15,000}\times100\) = 4% 20. Answer: (a) 29,484 Explanation: Let the rate of popukation be p,q,r respectively. Therefore, population after 3 years is \(=p(1+\frac{p}{100})(1+\frac{q}{100})\)\((1+\frac{r}{100})\) \(=2500\times(1+\frac{4}{100})(1+\frac{5}{100})\)\((1+\frac{8}{100})\) \(=25000\times\frac{26}{25}\times\frac{21}{20}\times\frac{27}{25}\) = 29,484 21. Answer: (a) 5% Explanation: It is given that simple interest in 2 years = Rs.400 ⇒ Simple interest for 1 year = Rs.200 ⇒ Hence, Compound interest for 1 year = Rs.200 ⇒ Given compound interest for 2 years = Rs. 410 ∴ Compound interest for 2 years = Compound interest 1st year + Compound interest 2nd year ⇒ Compound interest for 2nd year = Rs.410 - Rs.200 = Rs.210 ⇒ That is interest on Rs.200 for 1 year = Rs.210-Rs.200 = Rs.10 \(I=\frac{P\times T\times R}{100}\) \(10=\frac{200\times1\times R}{100}\) 2R = 10 R = 5% 22. Answer: (a) Rs. 800 Explanation: A= Rs. 968,T =2 years, R =10%,P=? \(A=P(1+\frac{R}{100}t)\) \(A=P(1+\frac{R}{100})^n\) \(968=P(1+\frac{10}{100})^2\) \(968=P(\frac{11}{10})^2\) \(P=\frac{968\times10\times10}{11\times11}\) P = Rs. 800 23. Answer: (b) 1:3 Explanation: Speed of cycle/Speed of scooter = 12/36 = 1/3 = 1:3 24. Answer: (b) Rs. 3000 Explanation: 10% VAT on Rs.100 will make it Rs.110 So, for price including VAT Rs.110, the original price is Rs.100 Then, Price including VAT Rs. 3300, the original price = Rs. \((\frac{100}{110}\times 3300)\) = Rs. 3000. 25. Answer: (c) 10 Explanation: Given, Amount = Rs. 220, Principle = Rs. 200, Time =1 year 1 year simple interest and compound interest are equal. So Interest =220−200 = Rs. 20 S. I = \(\frac{PRT}{100}\) \(R=\frac{S.I\times100}{P\times T}\) \(R=\frac{20\times100}{200\times1}\) R = 10% Click here Practice MCQ Question for Comparing Quantities Class 8 |
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