InterviewSolution
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InterviewSolution
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Classify each of the following complexes as either high or low spin . Explain your answers. (i) `[Co(H_(2)O)_(6)]^(2+) mu= 3.87 B.M. " " [Co(CN)_(6)]^(3-) mu=0.0 B.M.` (ii) `[Fe(NO_(2))_(6)]^(4-) mu=0.0 B.M." "[Fe(H_(2)O)_(6)]^(3+) mu =5.94 B.M. ` |
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Answer» (i) Each contain `Co^(2+)` ions in an octahedral field. Obvioulsy compound `[Co(H_(2)O)_(6)]^(2+)` is a high spin having magnetic moment value of 3.87 B.M. whereas `[Co(CN)_(6)]^(3-)` is low spin with a magnetic moment value of 0.0 B.M. (ii) The complex `[Fe(NO_(2))_(6)]^(4-)` contain `Fe^(2+)` which belongs to a `d^(6)` system . As the magnetic moment of the complex is zero , it indicates that all 6 electrons are paired up hence the compound is low spin on the other hand the magnetic moment of the 5.94 B.M. for the complex `[Fe(H_(2)O)_(6)^(3+)` corresponds to five unpaired electron in `Fe^(3+)` . It indicates , there is no pairing of d-electrons of `Fe^(3+)` ion . Hence complex is high spin . |
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