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Classify the elementshaving atomicnumberas givenbelowinto threeseparate pairs onthe basisof similarchemicalproperties: 9, 12, 16 , 34 , 53 , 56 Givetheirbriefelectronicexplanation. |
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Answer» Solution :The secondperiodends atatomic number10while the thirdperiodends atatomicnumber 18. Therefore9, 12and 16are the firstelementsin theirrespective GROUPS. Theatomicnumber ofthe otherelementsofthe same groupscan bededuced byadding magic numbers of 8 ,18 ,18and 32to the atomicnumbersoftheelementsof 2ndperiodor byaddingmagic NUMBER of 18, 18 and 32to theelementsof 3rdperiod.Thus `9 + 8 + 18+ 18 = 53` `12 + 8+ 18+ 18 =56` ` 16 + 18=34` elements withatomicnumbers9 ( F )and 53 ( I ) belongto halogenfamily (Group 17) , elements withatomic numbers 12(Mg )and 56 (Ba )belongto alkaline earthmetals(Group 2 ) while elementswithatomicnumbers16(S)and 34 (Se )belong to oxygenfamily(Group 16 ) Forelectronicconfigurationarefer to thetext. |
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