1.

CO is isoelectronic with

Answer»

`NO^(+)`
`N_(2)`
`SnCl_(2)`
`NO_(2)^(-)`

Solution :(A,B)
Electrons present in CO = 6 + 8 = 14
Then, In `NO^(+) ` = 7 + 8- 1 = 14
In `N_(2) ` = 7 + 7 = 14
In `SnCl_(2) ` = (very high) 50 + 17 `xx` 2
= 50 + 34 = 84
In `NO_(2)^(-) = 7 + 16 + 1 = 24 `


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