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Co-ordination number and oxidation state of Cr in K_(3) [Cr(C_(2)O_(4))_(3)]are, respectively |
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Answer» 3 and + 3 `implies` BIDENTATE ligand , So C.No = 6 `K_3[ulCr(C_2O_4)_3],+3+x+6=,x=+3` |
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