Cobalt (III) chloride forms several octahedral complexes with amonia. Which of the following will not give test for chloride ions with silver nitrate at `25^@C`?A. (a) `CoCl_3*5NH_3`B. (b) `CoCl_3*6NH_3`C. (c) `CoCl_3*3NH_3`D. (d) `CoCl_3*4NH_3`

Cobalt (III) chloride forms several octahedral complexes with amonia.

1.	Cobalt (III) chloride forms several octahedral complexes with amonia. Which of the following will not give test for chloride ions with silver nitrate at `25^@C`?A. (a) `CoCl_35NH_3`B. (b) `CoCl_36NH_3`C. (c) `CoCl_33NH_3`D. (d) `CoCl_34NH_3`
Answer» Correct Answer - C For octahedral complexes, coordination number is 6. Hence, `CoCl_3 diamond 3NH_3`, i.e., `[Co(NH_3)_3diamondCl_3]` will not ionize and will not give test for `Cl^(-)` ions with silver nitrate.

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Cobalt (III) chloride forms several octahedral complexes with amonia. Which of the following will not give test for chloride ions with silver nitrate at `25^@C`?A. (a) `CoCl_3*5NH_3`B. (b) `CoCl_3*6NH_3`C. (c) `CoCl_3*3NH_3`D. (d) `CoCl_3*4NH_3`

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Cobalt (III) chloride forms several octahedral complexes with amonia. Which of the following will not give test for chloride ions with silver nitrate at `25^@C`?A. (a) `CoCl_35NH_3`B. (b) `CoCl_36NH_3`C. (c) `CoCl_33NH_3`D. (d) `CoCl_34NH_3`