Cobalt (III) chloride forms several octahedral complexes with amonia. Which of the following will not give test for chloride ions with silver nitrate at `25^@C`?A. `CoCl_(3)cdot3NH_(3)`B. `CoCl_(3)cdot4NH_(3)`C. `CoCl_(3)cdot5NH_(3)`D. `CoCl_(3)cdot6NH_(3)`

Cobalt (III) chloride forms several octahedral complexes with amonia.

1.	Cobalt (III) chloride forms several octahedral complexes with amonia. Which of the following will not give test for chloride ions with silver nitrate at `25^@C`?A. `CoCl_(3)cdot3NH_(3)`B. `CoCl_(3)cdot4NH_(3)`C. `CoCl_(3)cdot5NH_(3)`D. `CoCl_(3)cdot6NH_(3)`
Answer» Correct Answer - A `[Co(NH_(3))_(6)]Cl_(3)to[Co(NH_(3))_(6)]^(3+)+3Cl^(-)` `[Co(NH_(3))_(3)]Cl_(3)to[Co(NH_(3))_(3)Cl_(3)]` `[Co(NH_(3))_(4)Cl_(2)]Clto[Co(NH_(3))_(4)Cl_(2)]^(+)+Cl^(-)` `[Co(NH_(3))_(5)Cl]Cl_(2)to[Co(NH_(3))_(5)Cl]^(2+)+2Cl^(-)` So, `[Co(NH_(3)_(3)Cl_(3)]` does not ionise so does not give test for chloride ions

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Cobalt (III) chloride forms several octahedral complexes with amonia. Which of the following will not give test for chloride ions with silver nitrate at `25^@C`?A. `CoCl_(3)cdot3NH_(3)`B. `CoCl_(3)cdot4NH_(3)`C. `CoCl_(3)cdot5NH_(3)`D. `CoCl_(3)cdot6NH_(3)`

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