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Coefficient of x49 in the expansion of (x–1)(x–3)(x–5).........................(x–99) is (a) –992 (b) 1 (c) –2500(d) None of these |
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Answer» Correct option (c) –2500 Explanation: (x–1)(x–3)(x–5) ................ (x–99) = x50 – S1 x49 + S2 x 48 ............. Coefficient of x49 is – S1 = –(1+3+5+......+99) = –502 = – 2500 |
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