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: cof‘(coss——h) का मान बऱबर है |
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Answer» You can write7π/6as(π+π/6)Thus we can clearly see the angle falls in the third quadrant. And the cosine value in third quadrant is always negative. Hence,cos(π+π/6)=−cos(π/6) coming back to the questioncos−1[cos(7π/6)]=cos−1[−cos(π/6)]=π−cos−1[cos(π/6)]=π−π6=5π6 right answer |
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