Coffee costing 250 per kg was mixed with chicory costing Rs. 75 per k

1.	Coffee costing 250 per kg was mixed with chicory costing Rs. 75 per kg in the ratio 5:2 for a certain blend. If the mixture was sold at Rs.230 per kg, find the gain or loss percent.
Answer» Let × be the common multiple. Cost of 5 Kg of Coffee => 5 × = 250 × 5 = Rs.1250 Cost of 2 kg of Chicory => 2 × = 75 × 2 = Rs.150 Cost of Mixture is; 5 × + 2 × = 1250 + 150 7 × = 1400 × = 1400/7 = Rs.200 So, CP of Mixture = Rs.200 And SP of Mixture = Rs.230 Since, SP > CP. So, it is a case of Gain. Gain = SP – CP = 230 – 200 = Rs.30 Gain Percent = \(Gain\%=\frac{Gain\times100}{CP}\) \(=\frac{30\times100}{200}\) = 15%

Coffee costing 250 per kg was mixed with chicory costing Rs. 75 per kg in the ratio 5:2 for a certain blend. If the mixture was sold at Rs.230 per kg, find the gain or loss percent.

Answer»

Let × be the common multiple.

Cost of 5 Kg of Coffee => 5 × = 250 × 5 = Rs.1250

Cost of 2 kg of Chicory => 2 × = 75 × 2 = Rs.150

Cost of Mixture is;

5 × + 2 × = 1250 + 150

7 × = 1400

× = 1400/7 = Rs.200

So, CP of Mixture = Rs.200

And SP of Mixture = Rs.230

Since, SP > CP. So, it is a case of Gain.

Gain = SP – CP

= 230 – 200

= Rs.30

Gain Percent = \(Gain\%=\frac{Gain\times100}{CP}\)

\(=\frac{30\times100}{200}\)

= 15%