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Collision frequency (Z) of a gas at a particular pressure |
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Answer» decreases with the rise in temperature `= (1)/(2)` collision no. `xx N//V` or `Z = (1)/(2) sqrt2 PI bar(v) sigma^(2) N//V xx N//V` `= (1)/(sqrt2) pi bar(v) sigma^(2) ((N^(2))/(V^(2)))` or `Z prop T` SINCE `bar(v) prop T` |
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