1.

Collision frequency (Z) of a gas at a particular pressure

Answer»

decreases with the rise in temperature
increases with the rise in temperature
decreases initially and thereafter increases
unpreductable

Solution :Collision FREQUENCY = Collisions which all MOLECULES undergo in a unit volume per second
`= (1)/(2)` collision no. `xx N//V`
or `Z = (1)/(2) sqrt2 PI bar(v) sigma^(2) N//V xx N//V`
`= (1)/(sqrt2) pi bar(v) sigma^(2) ((N^(2))/(V^(2)))`
or `Z prop T` SINCE `bar(v) prop T`


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