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| 1. |
Colour of `KMnO_(4)` is decolourised without evolution of any gas. The radical present may beA. `SO_(4)^(2-)`B. `SO_(3)^(2-)`C. `Sn^(2+)`D. Both (b) and (C) |
| Answer» Both `SO_(3)^(2-)` and `Sn^(2+)` reduce `KMnO_(4)` without evolution of any gas. | |