Column 1 has the condition on circle and column 2 has the equation of

1.	Column 1 has the condition on circle and column 2 has the equation of circles.which one of them are matched correct? Column 1 column 2 1) Centre of origin and radius = 10 P) (x−8)(x+8)+(y−6)(y+6)=0 2) Extremeties of diameter are (8,6) and (-8,-6) Q) (x−6)(x+6)+(y−8)(y+8)=0 3) Centre is (1,-2) and radius is 4 R) x2 + y2 −2x + 4y − 11 = 0
Answer» Column 1 has the condition on circle and column 2 has the equation of circles.which one of them are matched correct? Column 1 column 2 1) Centre of origin and radius = 10 P) $(x - 8) (x + 8) + (y - 6) (y + 6) = 0$ 2) Extremeties of diameter are (8,6) and (-8,-6) Q) $(x - 6) (x + 6) + (y - 8) (y + 8) = 0$ 3) Centre is (1,-2) and radius is 4 R) $x^{2} + y^{2} - 2 x + 4 y - 11 = 0$

Column 1 has the condition on circle and column 2 has the equation of circles.which one of them are matched correct? Column 1 column 2 1) Centre of origin and radius = 10 P) (x−8)(x+8)+(y−6)(y+6)=0 2) Extremeties of diameter are (8,6) and (-8,-6) Q) (x−6)(x+6)+(y−8)(y+8)=0 3) Centre is (1,-2) and radius is 4 R) x2 + y2 −2x + 4y − 11 = 0

Answer»

Column 1 has the condition on circle and column 2 has the equation of circles.which one of them are matched correct?

Column 1 column 2

1) Centre of origin and radius = 10 P) $(x - 8) (x + 8) + (y - 6) (y + 6) = 0$

2) Extremeties of diameter are (8,6) and (-8,-6) Q) $(x - 6) (x + 6) + (y - 8) (y + 8) = 0$

3) Centre is (1,-2) and radius is 4 R) $x^{2} + y^{2} - 2 x + 4 y - 11 = 0$