Column 1Column 2Column 3(equation for(Equation of conic)locus in Colum

1.	Column 1Column 2Column 3(equation for(Equation of conic)locus in Column 2)Locus of point of(I)(x−1)2+(y2)2=(12x−5y+313)2(i)intersection of(P)x2+y2=16perpendicular tangentsLocus of foot of(II)7x2−16y2=112(ii)perpendicular from focus(Q)x2+y2=9upon any tangent(III)(iii)Equation of chord bisected(R)4x+5y−4=0x225+y216=1at(12,25)(IV)x2+y2=8(iv)Tangent to the curveat(S)24−10y+1=0(8,10) Which of the following is the only correct combination?
Answer» $\begin{matrix} C o l u m n 1 & C o l u m n 2 & C o l u m n 3 (equation for (Equation of conic) & locus in Column 2) Locus of point of (I) & (x - 1)^{2} + (y_{2})^{2} = (\frac{12 x - 5 y + 3}{13})^{2} & (i) & intersection of & (P) & x^{2} + y^{2} = 16 perpendicular tangents Locus of foot of (I I) & 7 x^{2} - 16 y^{2} = 112 & (i i) & perpendicular from focus & (Q) & x^{2} + y^{2} = 9 upon any tangent (I I I) & (i i i) & Equation of chord bisected & (R) & 4 x + 5 y - 4 = 0 \frac{x^{2}}{25} + \frac{y^{2}}{16} = 1 & a t (\frac{1}{2}, \frac{2}{5}) (I V) & x^{2} + y^{2} = 8 & (i v) & Tangent to the curveat & (S) & 24 - 10 y + 1 = 0 (8, 10) \end{matrix}$ Which of the following is the only correct combination?

Column 1Column 2Column 3(equation for(Equation of conic)locus in Column 2)Locus of point of(I)(x−1)2+(y2)2=(12x−5y+313)2(i)intersection of(P)x2+y2=16perpendicular tangentsLocus of foot of(II)7x2−16y2=112(ii)perpendicular from focus(Q)x2+y2=9upon any tangent(III)(iii)Equation of chord bisected(R)4x+5y−4=0x225+y216=1at(12,25)(IV)x2+y2=8(iv)Tangent to the curveat(S)24−10y+1=0(8,10) Which of the following is the only correct combination?

Answer»

$\begin{matrix} C o l u m n 1 & C o l u m n 2 & C o l u m n 3 (equation for (Equation of conic) & locus in Column 2) Locus of point of (I) & (x - 1)^{2} + (y_{2})^{2} = (\frac{12 x - 5 y + 3}{13})^{2} & (i) & intersection of & (P) & x^{2} + y^{2} = 16 perpendicular tangents Locus of foot of (I I) & 7 x^{2} - 16 y^{2} = 112 & (i i) & perpendicular from focus & (Q) & x^{2} + y^{2} = 9 upon any tangent (I I I) & (i i i) & Equation of chord bisected & (R) & 4 x + 5 y - 4 = 0 \frac{x^{2}}{25} + \frac{y^{2}}{16} = 1 & a t (\frac{1}{2}, \frac{2}{5}) (I V) & x^{2} + y^{2} = 8 & (i v) & Tangent to the curveat & (S) & 24 - 10 y + 1 = 0 (8, 10) \end{matrix}$

Which of the following is the only correct combination?

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment