{:("Column-I","Column-II"),("A) 16g of "O_(2),"P) 1gm atom of O"),("B) Gram molar volume of "H_(2)O,"Q) 22.4 lit at STP"),("C) 18 g of "H_(2)O,"R) 18 ml"),("D) 1/2 mole "O_(2)+1" gm atom of "H_(2),"S) 11.2 lit at STP"):}

{:("Column-I","Column-II"),("A) 16g of "O_(2),"P) 1gm atom of O"),("B)

1.	{:("Column-I","Column-II"),("A) 16g of "O_(2),"P) 1gm atom of O"),("B) Gram molar volume of "H_(2)O,"Q) 22.4 lit at STP"),("C) 18 g of "H_(2)O,"R) 18 ml"),("D) 1/2 mole "O_(2)+1" gm atom of "H_(2),"S) 11.2 lit at STP"):}
Answer» Solution :A) 16 gm = `(1)/(2)` mole = 11.2 lit at STP `=(1)/(2)xxg` atoms of O B) molar VOL = 22.4 lit at STP C) 18g `H_(2)O` implies 1 mole implies 1 mole of O = 18ml = 1GM atom of O D) total moles = `(1)/(2)+(1)/(2)=1 implies 22.4` lit at STP `(1)/(2)` mole `O_(2)=(1)/(2)xx2g` atoms of O