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`{:(,"Column-I",,"Column-II"),((A),BCl_(3),(P),3C -4e^(-)"bond is present in dimer"),((B),BeCl_(2),(Q),"Planar"),((C),PCl_(3),(R),"Change in hybridisation of the central atom during dimerisation"),((D),AsCl_(3),(S),"Tautomerism is observed during final product formation in hydrolysis process"),(,,(T),"Basicty of one of the hydrolysed product is three"):}` |
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Answer» Correct Answer - (A) Q (B) P,Q,R (C ) S (D) T (A) `BCl_(3)` does not dimerise, it is `sp^(2)` hybridised so planar on hydrolysis it gives `H_(3)BO_(3)` whose basicity is one. (B) sp hybridised planar `BeCl_(2)` dimerise give `Be_(2)Cl_(4)` in which Be is `sp^(2)` hybridised and hydrolysis product is `Be(OH)_(2).` (C ) `sp^(3)` hybridised `AsCl_(3)` is pyramidal in shape which gives `H_(3)AsO_(3)` which does not show tautomerism due to large size of As and basicity of `H_(3)AsO_(3)` is three. ] |
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