{:(,"Column - I",,"Column - II"),((A),"Boric acid",(P),Na_(2)[B_(4)O_(5)(OH)_(4)]),((B),"Kernite",(Q),K_(2)O.3Al_(2)O_(3).6SiO_(2).2H_(2)O),((C ),"Feldspar",(R ),Al_(2)O_(3).2SiO_(2).2H_(2)O),((D),"Mica",(S),KAlSi_(3)O_(8)),((E ),"Kadonite",(T),H_(3)BO_(3)),((F),"Diaspar",(U),Al_(2)O_(3)H_(2)O):}

{:(,"Column - I",,"Column - II"),((A),"Boric acid",(P),Na_(2)[B_(4)O_(

1.	{:(,"Column - I",,"Column - II"),((A),"Boric acid",(P),Na_(2)[B_(4)O_(5)(OH)_(4)]),((B),"Kernite",(Q),K_(2)O.3Al_(2)O_(3).6SiO_(2).2H_(2)O),((C ),"Feldspar",(R ),Al_(2)O_(3).2SiO_(2).2H_(2)O),((D),"Mica",(S),KAlSi_(3)O_(8)),((E ),"Kadonite",(T),H_(3)BO_(3)),((F),"Diaspar",(U),Al_(2)O_(3)H_(2)O):}
Answer» Solution :(A) Boric acid - formula is `H_(3)BO_(3)` (B) Kernite - formula is `Na_(2)[B_(4)O_(5)(OH)_(4)]` (C ) Feldspar - formula is `Kal Si_(3)O_(8)` (D) MICA - formula is `K_(2)O.3Al_(2)O_(3).6SiO_(2).2H_(2)O` (E ) Kadonite - formula is `Al_(2)O_(3).2SiO_(2).2H_(2)O` (F) Diaspar - formula is `Al_(2)O_(3)H_(2)O`