{:(,"Column-I",,"Column-II"),("A)","One gram molecules of oxygen gas","P)","one mole of "H_(2)),("B)","Gram molar volume of "H_(2),"Q)","one mole of "O_(2)),("C)","44 gm of "CO_(2),"R)","22.4lit at STP"),("D)","18 gm water","S)",3N_(A)" atoms"):}

{:(,"Column-I",,"Column-II"),("A)","One gram molecules of oxygen gas",

1.	{:(,"Column-I",,"Column-II"),("A)","One gram molecules of oxygen gas","P)","one mole of "H_(2)),("B)","Gram molar volume of "H_(2),"Q)","one mole of "O_(2)),("C)","44 gm of "CO_(2),"R)","22.4lit at STP"),("D)","18 gm water","S)",3N_(A)" atoms"):}
Answer» SOLUTION :A) 1 gm MOLECULE `O_(2)` = 1 mole `O_(2)` = 22.4 lit at STP B) gram molar of `H_(2)` = 1 mole = 22.4 lit at STP C) 44 gm = 1 mole of `CO_(2)` = 1 mole of `O_(2)` = 22.4 lit. at STP = `N_(0)` molecules = `3N_(0)` atoms D) 18 gm `H_(2)O` = 1 mole of `H_(2)O` = 1 mole of `H_(2)=3N_(0)` atoms