Column I shows different charge distributions and short electric dipole at a distance x from the charge distributions. Column II gives the dependence of force acting on the dipole as of function of x.

Column I shows different charge distributions and short electric dipol

1.	Column I shows different charge distributions and short electric dipole at a distance x from the charge distributions. Column II gives the dependence of force acting on the dipole as of function of x.
Answer» <P> Solution :(P) Electric field due to uniformly `=SIGMA/(2 epsi_(0))` Charge thin INFINITE disc `F_("net")` on DIPOLE `=0` (Q) Electric filed due to uniformaly `=sigma_(x)/epsi_(0)` charged infinite `F_("net")` on dipole `=(rho ql)/epsi_(0)` (R) Electric field due to uniform `=(2kl)/(x)` infinite line of charge `F_("net")` on.dipole `=(-2kl)/(x(x+l)) ~~(-2k lambda l)/x^(2)` (S) Electric field due to uniformly `=(KQ)/x^(2)` charged sphere `F_("net")` on dipole `=(-KQq(2xl))/(x^(2)(x+l)^(2))~~(-KqQ(2xl))/x^(4)` `~~(-2KqQl)/x^(3)`