{:(,"Column I( Solutions mixed)",,"Column II ( Heat evolved)"),((A),500 mL of 0.1 "M HCl acid"+200 mL of 0.2 M NaOH "solution",(p),4568J),((B),200 mLof 0.2MH_(2)SO_(4) + 400 mL of 0.5 M KOH "solution",(q),2284J),((C ),500 mL of 0.1M HCl+ 500 mL of 0.1 M NH_(4)OH,(r),2760 J),((D),500 mL of 0.1 M "acetic acid " + 500 mL of 0.1 M NaOH ,(s),2575J):} (a)A-r,B-p,C-s,D-q(b) A-p, B-r, C-q,D-s(c )A-q,B-p, C-s, D-r(d) A-,B-s,C-p,D-r

{:(,"Column I( Solutions mixed)",,"Column II ( Heat evolved)"),((A),50

1.	{:(,"Column I( Solutions mixed)",,"Column II ( Heat evolved)"),((A),500 mL of 0.1 "M HCl acid"+200 mL of 0.2 M NaOH "solution",(p),4568J),((B),200 mLof 0.2MH_(2)SO_(4) + 400 mL of 0.5 M KOH "solution",(q),2284J),((C ),500 mL of 0.1M HCl+ 500 mL of 0.1 M NH_(4)OH,(r),2760 J),((D),500 mL of 0.1 M "acetic acid " + 500 mL of 0.1 M NaOH ,(s),2575J):} (a)A-r,B-p,C-s,D-q(b) A-p, B-r, C-q,D-s(c )A-q,B-p, C-s, D-r(d) A-,B-s,C-p,D-r
Answer» Solution :A. REFER to Solved Problem B. Refer to Solved Problem C. Enthalpy of neutralization`NH_(4)OH` with HCl`= 51.5 kJ mol^(-1)=51500 J mol^(-1)` 500mLof 0.1 M `NH_94)OH =500 XX 0.1` millimoles`=50` millimole`= 0.05` mole `:. `Enthalpy of neutralisation. `=51500 xx 0.05 J = 2575J`. D. Enthalpy of neutralisation of ACETICACID with NAOH `=55.2 kJ mol^(-1) = 55200 J mol^(-1)` 500mL of 0.1 M NaOh` =500 xx 0.1 ` millimole `= 50` millimole `= 0.05 ` mole `:. `Enthalpy ofneutralisation `=55 200 xx 0.05 J = 2760 J`.