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Column IColumn IIa. If∫2x√1−4xdx=ksin−1(f(x))+c, p. 0 then k is greater than b. If∫(√x)5(√x)7+x6dx=alnxkxk+1+c, q. 1 then ak is less than c. If∫x4+1x(x2+1)2dx=kln|x|+m1+x2+n, r. 3 where n is the constant of integration, then mk is greater than d. If∫dx5+4cosx dx=ktan−1(mtanx2)+c,s. 4 then k/m is greater than Which of the following is the correct combination?

Answer» Column IColumn IIa. If2x14xdx=ksin1(f(x))+c, p. 0 then k is greater than b. If(x)5(x)7+x6dx=alnxkxk+1+c, q. 1 then ak is less than c. Ifx4+1x(x2+1)2dx=kln|x|+m1+x2+n, r. 3 where n is the constant of integration, then mk is greater than d. Ifdx5+4cosx dx=ktan1(mtanx2)+c,s. 4 then k/m is greater than

Which of the following is the correct combination?




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