Combustion of 0.42g of a compound gave 0.924gCO_(2) and 0.243g H_(2)O. Due to distillation of 0.208g of compound with NaOH, ammonia evolved required 30mL of (N)/(20)H_(2)SO_(4) for complete neutralization. Vapour density of the compound is 69.5. The compound has empirical formula:

Combustion of 0.42g of a compound gave 0.924gCO_(2) and 0.243g H_(2)O.

1.	Combustion of 0.42g of a compound gave 0.924gCO_(2) and 0.243g H_(2)O. Due to distillation of 0.208g of compound with NaOH, ammonia evolved required 30mL of (N)/(20)H_(2)SO_(4) for complete neutralization. Vapour density of the compound is 69.5. The compound has empirical formula:
Answer» `C_(7)H_(9)O_(2)N` `C_(6)H_(5)NO_(2)` `C_(3)H_(7)-CONH_(2)` `NH_(2)-OVERSET(O)overset(\|\|)(C)-NH_(2)` Answer :A