Combustion of 0.42g of a compound gave 0.924gCO_(2) and 0.243g H_(2)O. Due to distillation of 0.208g of compound with NaOH, ammonia evolved required 30mL of (N)/(20)H_(2)SO_(4) for complete neutralization. Vapour density of the compound is 69.5. What is the value of 'n' for the given compound? where n = ("Molecular mass")/("Empirical formula mass")

Combustion of 0.42g of a compound gave 0.924gCO_(2) and 0.243g H_(2)O.

1.	Combustion of 0.42g of a compound gave 0.924gCO_(2) and 0.243g H_(2)O. Due to distillation of 0.208g of compound with NaOH, ammonia evolved required 30mL of (N)/(20)H_(2)SO_(4) for complete neutralization. Vapour density of the compound is 69.5. What is the value of 'n' for the given compound? where n = ("Molecular mass")/("Empirical formula mass")
Answer» 2 3 1 4 Answer :C