Combustion of a gaseous hydrocarbon give 0.25 g water. What will be empricial formula of the hydrocarbon ?

Combustion of a gaseous hydrocarbon give 0.25 g water. What will be em

1.	Combustion of a gaseous hydrocarbon give 0.25 g water. What will be empricial formula of the hydrocarbon ?
Answer» `C_(2)H_(4)` `C_(2)H_(6)` `C_(3)H_(4)` `C_(7)H_(8)` Solution :`H_(2)O= 0.72 G = (0.72)/(18) = 0.04 "mole" H_(2)O` `CO_(2) = 3.08g = (3.08)/(44) = 0.07 "mole" CO_(2)` `:.` Mole of `C= 0.07` `:.` Mole of `H = 2 (0.04)= 0.08` `:.` PROPORTION of `C : H` `= 0.07 : 0.08` Empirical formula `=C_(7)H_(8)`