1.

Combustion of sucrose is used by aerobic organisms for providing energy for the life substaining process. If all the capturing from the reaction is done through electrical process (non P-V work) then calculate maximum available energy which can be captured by combustion of 34.2 gm of sucrose Given : Delta H_("sucrose") = -6000 kJ mol^(-1) , Delta S_("combustion") = 180 J// K mol and body temperature is 300 K.

Answer»

600kJ
594.6 kCal
144.83 k Cal
605.4 kJ

Solution :Non-PV work is notihing but `Delta G`
So `Delta G` per mole `= Delta H - T Delta S`
`= -60000 xx 10^(3) - 300(180)`
`= -6054 kJ`
`Delta G` per 34.2 GR `= (-6054)/(10) = - 605.4 KJ`


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