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Combustion of sucrose is used by aerobic organisms for providing energy for the life substaining process. If all the capturing from the reaction is done through electrical process (non P-V work) then calculate maximum available energy which can be captured by combustion of 34.2 gm of sucrose Given : Delta H_("sucrose") = -6000 kJ mol^(-1) , Delta S_("combustion") = 180 J// K mol and body temperature is 300 K. |
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Answer» 600kJ So `Delta G` per mole `= Delta H - T Delta S` `= -60000 xx 10^(3) - 300(180)` `= -6054 kJ` `Delta G` per 34.2 GR `= (-6054)/(10) = - 605.4 KJ` |
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