Comment upon the nature of the roots without solving 1.). X�

1.	Comment upon the nature of the roots without solving 1.). X2 - as - b2 = 0 When I solved the equation I got the roots as A2 + 4b2 But the answer is given as the roots are positive so it is real and unequal how is it? And why is it? A's value can be a negative no also like a= -3 So how can this be possible?
Answer» Comment upon the nature of the roots without solving 1.). X² - as - b² = 0 When I solved the equation I got the roots as A² + 4b² But the answer is given as the roots are positive so it is real and unequal how is it? And why is it? A's value can be a negative no also like a= -3 So how can this be possible?

Comment upon the nature of the roots without solving 1.). X2 - as - b2 = 0 When I solved the equation I got the roots as A2 + 4b2 But the answer is given as the roots are positive so it is real and unequal how is it? And why is it? A's value can be a negative no also like a= -3 So how can this be possible?

Answer»

Comment upon the nature of the roots without solving

1.). X² - as - b² = 0

When I solved the equation I got the roots as

A² + 4b²

But the answer is given as the roots are positive so it is real and unequal how is it? And why is it?

A's value can be a negative no also like a= -3

So how can this be possible?

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