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Commenton the reactions of dihydrogen with (i) chloride (ii) sodium, and (iii) copper (II) oxide. |
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Answer» Solution :a) Whenhydrogen reacts with CHLORINE, an electron pain is shared between H and Cl leading to the FORMATION of hydrogen CHLORIDE. `H_(2)+Cl_(2)to2HCl` b) Dihydrogen REDUCES copper (II) oxide to copper and itself gets oxidised to WATER. `H_(2) +CuOtoCu+H_(2)O` |
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