1.

Commercial sample of H_(2)O_(2) is labelled as 10 V. Its % strength is nearly

Answer»

3
6
9
12

Solution :Applying the FORMULA , we have , Volume STRENGTH = `5.6xx("Percentage strength")/("EQ. wt. of " H_(2)O_(2))xx10`
or `10=(5.6 xx "Percentage strength")/(17)xx10`
Percentage strength =`(17)/(5.6)=3.03~=3`


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