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Common salt obtained from sea water contains `95% NaCl` by mass. The appoximate number of molecules present in `10.0g` of the salt isA. `10^(21)`B. `10^(22)`C. `10^(23)`D. `10^(24)` |
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Answer» Correct Answer - C 58.5 g of NaCl contains `6.023xx10^(23)` molecules. 10 g will contain `1.03xx10^(23)` molecules of NaCl. Since it contain 95 % NaCl, so total number of molecules `=95/100xx1.03xx10^(23)= 0.98xx10^(23) or 10^(23)` |
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