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Common salt obtained from sea water contains `95% NaCl` by mass. The appoximate number of molecules present in `10.0g` of the salt isA. `10^(24)`B. `10^(23)`C. `10^(22)`D. `10^(21)` |
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Answer» Correct Answer - B `m_(NaCl) = 95%` of `10g = 9.5g` ? Fomula units `NaCl = 9.5g NaCl xx (1 mol NaCl)/(58.5g NaCl)` `xx (6.022xx10^(23) "formula units")/(1 mol NaCl)` `= (57.209)/(58.5) xx10^(23)` formula units `= 10^(23)` formula unit |
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