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Compare the components for the following vector equations (a) vecF=mveca Here m is a positive number (b) vecp=0 |
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Answer» Solution :`vecF=mveca` `F_(x)hati+F_(y)hatj+F_(z)hatk=ma_(x)hati+ma_(y)hatj+ma_(z)hatk` By comparing the COMPONENTS, we get `F_(x)=ma_(x),F_(y)=ma_(y),F_(z)=ma_(z)` This implies that one vector EQUATION is equivalent to three scalar EQUATIONS. Case (B): `vecP=0` `p_(x)hati+p_(y)hatj+p_(z)hatk=0hati+0hatj+0hatk` By comparing the components, we get `p_(x)=0,p_(y)=0,p_(z)=0` |
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