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Compare the rates of diffusion of ""^(235)UF_(6) and ""^(238)UF_(6). |
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Answer» SOLUTION :MOLECULAR mass of `""^(235)UF_(6)=235+6xx19=349` , Molecular mass of `""^(238)UF_(6)=238+6xx19=352` `:. (r_(1)(""^(235)UF_(6)))/(r_(2)(""^(238)UF_(6)))=sqrt((M_(2))/(M_(1)))=sqrt((352)/(349))=1.004` THUS,`R(""^(235)UF_(6)) : r(""^(238)UF_(6))=1.004 : 1` |
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