Compare the relative stability of the following species and indicate the magnetic properties : O_(2), O_(2)^(+) , O_(2)^(-) (supper oxide) : O_(2)^(2-) (Peroxide)

Compare the relative stability of the following species and indicate t

1.	Compare the relative stability of the following species and indicate the magnetic properties : O_(2), O_(2)^(+) , O_(2)^(-) (supper oxide) : O_(2)^(2-) (Peroxide)
Answer» SOLUTION :Electron configuration and bond order of `O_(2), O_(2)^(+) , O_(2)^(-)` : `O_(2)^(2-)` : Total electron = 16 + 2= 18 Electron configuration in MO for `O_(2)^(2-)` : , `(sigma_(1s))^(2) (sigma_(1s)^())^(2) (sigma_(2s))^(2) (sigma_(2s_(Z)))^(2) (pi_(2p_(x)))^(2) (pi_(2p_(y)))^(2) (pi_(2p_(x))^())^(2)(pi_(2p_(y))^(**))^(2) ` Bond order of `O_(2)^(2-) = (1)/(2) (N_(b) - N_(a)) ` = `(1)/(2) ( 10 - 8 )` = 1 Stability : Bond order increase, as stability increase. The order of stability or under `O_(2)^(+) (2.5) GT O_(2) (2.0) gt O_(2)^(-) (1.5) gt O_(2)^(2-) (1.0)` `larr` bond order and stability increase `larr` Magnetic property : One more unpaired electron so `O_(2) , O_(2)^(+) , O_(2)^(-)` PARAMAGNETIC and in `O_(2)^(2-) ` all electron are paired , so `O_(2)^(2-)` is diamagnetic .