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Complete combustion of 0.858 g of compound X gives 2.63 g of `CO_(2)` and 1.28 g of` H_(2)`O. The lowest molecular mass X can haveA. (a)43 gB. (b)86 gC. (c )129 gD. (d)172 g |
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Answer» Correct Answer - A `%C=12/44xxW_(CO_(2))/Wxx100=12/44xx2.63/0.858xx100=83.6%` `%H=2/18xxW_(H_(2)O)/Wxx100= =2/18xx1.28/.858xx100=16.4%` `{:(,%(a),At.wt.(b),a//b,Ratio),(C,83.6,12,6.96,1),(H,16.4,1,16.4,2.3):}` `C_(3)H_(7)=12xx3+7=43 g`. |
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