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InterviewSolution
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Complete combustion of a hydrocarbon gives 0.66 g of `CO_(2)` and 0.36g of `H_(2)O`. Find the empirical formula of the compound. |
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Answer» Let the mass of the substance taken = w g `:. % C = (12)/(44) xx(0.66)/(w) xx 100 = (18)/(w)` and `% H = (2)/(18) xx (0.36)/(w) xx 100 = (4)/(w)` Ratio of atoms, `C : H = (18)/(w) xx (1)/(12) : (4)/(w) xx (1)/(1) = 3 : 8` Hence, E.F. = `C_(3)H_(8)`. |
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