Complete combustion of C_(4)H_(10), CO_(2) is a by product. Where C_(4)H_(10) has its isomers on oxidation it gives alcohol as by product. Give reaction and explain them ?

Complete combustion of C_(4)H_(10), CO_(2) is a by product. Where C_(4

1.	Complete combustion of C_(4)H_(10), CO_(2) is a by product. Where C_(4)H_(10) has its isomers on oxidation it gives alcohol as by product. Give reaction and explain them ?
Answer» Solution :`C_(4)H_(10)` complete OXIDATIO combustion gives `CO_(2)`, there is oxidation. In these C-C and C-H bonds are broken. `underset("Butane")(C_(4)H_(10(g))) + (13)/(2)O_(2(g)) rarr 4CO_(2(g)) + 5H_(2)O_((L)) + 2875/84 kJ mol^(-1)` `C_(4)H_(10)` gas is used as fuel. Isomer of `C_(4)H_(10)`, formation of ALCOHOL there is bond C-H oxidises to C-C and the other bonds C-C and C-H are not broken. `underset("2-Methylpropane")((CH_(3))_(3)C-H) overset(KMnO_(4), (O)^(+))rarr underset("2-Methylpropane-2-ol")((CH_(3))_(3)C-OH)` `C_(4)H_(10)("Butane") ""rarr "Alcohol"` Butane is not used as fuel but reaction gets oxidizes.