1.

Complete the entire in the third column of the table.S.No.EquationValue of variableEquation satisfied yes/noa10y = 80y = 10b10y = 80y = 8c10y = 80y = 5d4l = 20l = 20e4l = 20l = 80f4l = 20l = 5gb + 5 = 9b = 5hb +5 = 9b = 9ib + 5 = 9b = 4jh - 8 = 5h = 13kh - 8 = 5h = 8lh - 8 = 5h = 0mp + 3 = 1p = 3np + 3 = 1p = 1op + 3 = 1p = 0pp + 3 = 1p = -1qp + 3 = 1p = - 2

Answer»

(a) 10y = 80

y = 10 is net a solution to the given equation because for y = 10

10y = 10 × 10 = 100, and net 80

(b) 10y = 80

y = 8 is a solution to the given equation because for y = 8

10y = 10 × 8 = 80 and hence, the equation is satisfied

(c) 10y = 80

y = 5 is net a solution to the given equation because for y = 5

10y = 10 × 5 = 50, and net 80.

(d) 4l = 20

l = 20 is net a solution to the given equation because for l = 20

4l = 4 × 20 = 80, and net 20

(e) 4l = 80

l = 80 is net a solution to the given equation because for l = 80

4l = 4 × 80 = 320, and net 20

(f) 4l = 20

4l = 4 × 5 = 20 and hence, the equation because for l = 5

4l = 4 × 5 = 20 and hence, the equation is satisfied

(g) b + 5 = 9

b = 5 is net a solution to the given equation because for b = 5

(h) b + 5 = p

b = 9 is net a solution to the given equation because for b = 9

b + 5 = 9 + 5 = 14, and net 9

(i) b + 5 = 9

b + 5 = 4 + 5 = 9 and hence, the equation is satisfied

(j) h – 8 = 5

h = 13 is a solution to the given equation because for h = B

h – 8 = 13 – 8 = 5 and hence, the equation is satisfied

(k) h – 8 = 5

h = 8 is net a solution to the given equation because for h = 8

h = 8 = -8 = 0, and net 5

(l) h – 8 = 5

h = 0 is net a solution to the given equation because for h = 0,

h – 8 = 0 – 8 = -8, and net 5

(m) p + 3 = 1

p + 3 = 3 + 3 = 6, and net 1

(n) p + 3 = 1

p + 3 = 1 + 3 = 4 , and net 1

(o) p + 3 = 1

p + 3 = 0 + 3 = 3, and net 1

(p) p + 3 = 1

p + 3 = -1 + 3 = 2, and net 1

p + 3 = -2 + 3 = 1 and hence, the equation is satisfied.


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