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Complete the following nuclear reactions :(i) 20884Po → 20482Pb + ........(ii) 3215P → 3216S + .......... |
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Answer» We have (i) 20884Po → 20482Pb + 42He + Q (Also accept if Q is not written) (ii) 3215P → 3216S + 0-1e + v [Also accept if r.r is not written] |
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