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Complete the following reactions: `I.underset((Excess))(8NH_(3))+3Cl_(2)rarrI` `II.underset((Excess)) (NH_(3)+3Cl_(2)rarrII` |
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Answer» Correct Answer - A (I)` underset((" Excese"))8NH_(3) + 3Cl_(2) to 6NH_(4)Cl+ N_(2)` (II) `NH_(3)+ underset (("Exces"))3Cl_(2) to NCl_(3)+ 3HCl` |
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